Splet18. avg. 2024 · Find an answer to your question Describe existence of pbf4?? Hello friend... Chlorine is a stronger oxidising agent and so can easily oxidise lead from +2 oxidation state to +4 oxidation state, therefore, PbCl4 exists whereas PbBr4 and Pbl4 do not exist because bromine and iodine are weaker oxidising agents and so cannot oxidise Pb2+ to Pb4+. SpletStatement 1: FeI3, CuI2, PbI4 do not exist but FeF3, CuF2, PbF4 exist. Statement 2: F2 having highest oxidising power whereas I2 having least oxidising power among halogens Q. Statement 1: F eI 3,C uI 2,P bI 4 do not exist but F eF 3,C uF 2,P bF 4 exist.
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Splet02. apr. 2024 · Complete answer: Coordinate bond is a type of covalent bond formed between two different atoms in which the electron pair is shared by both the atoms but both the electrons are shared by only one species. The species that is donating the electron pair is known as a Lewis base and the species that accepts the electron pair is known as a … SpletAnswer (1 of 3): PbI4 and PbBr4 on dissociation form I- and Br- resp which are strong reducing agents. They get oxidised to I2 and Br2 resp and reduce Pb4+ to Pb2+ in both the cases. There is no such scenario in case of PbCl4 which justifies its existence. PbI4 and PbBr4 on dissociation form I- and Br- resp which are strong reducing agents. how do you use a totem of undying
PbI4 Does Not Exist Because? - BYJU
SpletP bF 4, P bCl4 exists but P bBr4 and P bI 4 do not exist because of: A Large size of Br– and I– B Strong oxidising character of P b4+ C Strong reducing character of P b4+ D Low electronegativity of Br– and I– Solution The correct option … Splet(i) PbF 4 is not covalent in nature. Because Pb atom is very & F atom is very small, so according to Fajan's rule, PbF 4 is not covalent. (ii) SiCl 4 is not a very stable compound because of steric hindrance thus can be hydrolysed very easily (iii) GeX 4 is more stable than GeX 2 as in GeX 4 all the orbitals are fully filled. Splet29. jun. 2024 · The existence of IF7 and non-existence of IBr7 can be explained on the basis of electronegativity and the size of atoms. - Fluorine is the most electronegative element in the periodic table. - Moreover, its size is also very small. - Due to this, it can form 7 bonds with iodine very easily and form IF7. phoning finland from uk